Leftmost and rightmost nodes of binary tree | JAVA | GFG POTD | Java Solution | Apna Coding
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Leftmost and rightmost nodes of binary tree | JAVA | GFG POTD | Java Solution | Apna Coding
In computer science and data structures, a binary tree is a hierarchical data structure where each node has at most two children, referred to as the left child and the right child. We will discuss how to find the leftmost and rightmost nodes of a binary tree in Java.
Algorithm:
To find the leftmost and rightmost nodes of a binary tree, we can perform a level-order traversal (also known as breadth-first traversal) of the tree. This traversal visits nodes level by level, starting from the root node and moving to the leftmost child, then the next level, and so on. During this traversal, we keep track of the leftmost and rightmost nodes at each level.
Here's a step-by-step algorithm:
Initialize an empty queue to perform level-order traversal.
Enqueue the root node into the queue.
Initialize variables leftmost and rightmost to null. These variables will store the leftmost and rightmost nodes at the current level.
While the queue is not empty:
a. Get the number of nodes at the current level by checking the size of the queue.
b. Iterate through the nodes at the current level:
i. Dequeue a node from the front of the queue.
ii. If it's the first node at the current level, assign it to leftmost.
iii. If it's the last node at the current level, assign it to rightmost.
iv. Enqueue the left and right children of the current node if they exist.
After the traversal is complete, leftmost will contain the leftmost node, and rightmost will contain the rightmost node.
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